ELEKTRONIKA
1 inch = 0.0254 meters, 1 pound mass (LBM) = 0.45359237 kg
Example: Joule = N.m = kg.m/det2.m
So joule unit dimensions are: (ML/S2). L = ML2S-2
Newton dimensions = MLS-2
Joule-2 dimensions = ML2S
a. Electrostatic Discharge
Electric force consists of two kinds, namely:
1. Electric force of mutual attraction (not similar)
2. Style electric repulsion (similar)
* Active electric circuit
-A (ampere)
-V (volts)
passive electrical circuits
-R, L, C
* Active electronic components
-Diode
-Transistor
Passive electronic components
-R, L, C
======================================
Formula
A.konduktansi
conductance = G
G = I / R Rb.Rumus
-Series: RT = R1 + R2 + R3
-Parallel: RT = R2 + i.i/R1
Formula Conversion from Delta to Wye
R1 = (RB RC) / (RA + RB + RC)
R2 = (RC RA) / (RA + RB + RC)
R = (RA RB) / (RA + RB + RC)
Conversion formula from Wye to Delta:
RA = (R1 + R2 + R3 R1 R2 R3) / R1
RB = (R1 + R2 + R3 R1 R2 R3) / R2
RC = (R1 + R2 + R3 R1 R2 R3) / R3
R = p.A / l
where:
R is the resistance in ohms
A is the cross-sectional area in m2
l is the length of wire (m)
Coil (inductor)
V (t) = L di / dt ........... (2.6.)
i (t) = 1 / L f v (t) dt ..... (2.7.)
i = C. dv / dt
Comparison of Voltage and Current In Passive Elements
VOLTAGE RANGE CURRENT (AMPERE)
Resistance (R) V (t) = i (t). R i (t) = V (t) / R
Inductor (L) V (t) = L di / dt I (t) = 1 / L f V (t) dt
Capacitor (C) V (t) = 1 / C fi (t) DTI (t) = C dv / dt
Kirchoff law
Formulated by Gustav Robert Kirchoff
a.Hukum Kirchoff Voltage (Kirchoff's Voltage Law = KVL)
Algebraic sum of the voltage sources in a circuit
enclosed voltage equal to the number of falls (voltage
drop) in the circuit. V = V1 + V2 + V3
b. Kirchoff's Current Law (Kirchoff's Current Law = KCL)
The number of incoming flows at a node will be the same
the amount of current leaving the node
in a closed circuit.
Inflow = outflow
i3 + i1 + i2 + i5 = i4 + i6
i3 + i5 + i1 - i2 - i4 - i6 = 0
a.2. The voltage divider resistors in series three
According to Kirchoff's Voltage Law:
VAB = V; VAP = V1; VPQ = V2; VQB = V3 and i = i1 = i2 = i3
so that V = V1 + V2 + V3
According to Ohm's Law: V = i. R and
Req = R1 + R2 + R3 then the flow of each;
i = V / R1 + R2 + R3
i1 = (R1 / R1 + R2 + R3). V
i2 = (R2 / R1 + R2 + R3). V
i3 = (R3 / R1 + R2 + R3). V
1.jpg)